Question

Please answer it plzzzzzzzzzzzz

Answer 1

Original height of tree = 15 m

Let the length of standing part of tree be x.

Then the length of broken part of tree be 15 - x.

sin 60° = $\frac{perpendicular}{height}$

⇒ $\frac{\sqrt{3} }2}$  = $\frac{x}{15-x}$

⇒$15\sqrt{3} -\sqrt{3} x=2x$

⇒$15\sqrt{3} = 2x + \sqrt{3} x$

⇒$15\sqrt{3} = (2 + \sqrt{3} )x$

⇒$x = \frac{15\sqrt{3} }{2+\sqrt{3} }$

Rationalize

= $\frac{15\sqrt{3} }{2+\sqrt{3} }$ × $\frac{2-\sqrt{3} }{2-\sqrt{3} }$

= $\frac{30\sqrt{3} -45}{4+2\sqrt{3} -2\sqrt{3} -3}$

=$30\sqrt{3} -45$

Given $\sqrt{3} = 1.73$

= (30 × 1.73) - 45

= 51.9 - 45

= 6.9 m

Hope I go that right. Diagram included below.