please answer it ???properly
spammmers stay away ??.
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Answer :
☞ Option A
☞ 2000 R ( 1 / 2 + In 4 / 3 )
Explanation :
A → B is an isobaric process,
V = T
so, W( AB ) = nRΔT
= 2 × R × ( 750 - 250 )
= 1000 R
B → C is an isochoric process,
ΔW( BC ) = 0
C → D is an isothermal process,
ΔW( CD ) = nRT ln ( Vf / Vi )
= 2 × R × 1000 In ( 20 / 15 )
= 2000 R In ( 4 / 3 )
Total work done, ΔW = ∑ΔW( AB )
ΔW = ΔW( AB ) + ΔW( BC ) + ΔW( CD )
= nRΔT + 0 + nRTIn V2 / V1
= 2 R ( 750 - 250 ) + 0 + 2R × 1000 ( In 4 / 3 )
= 1000 R + 2000 In 4 / 3
= 2000 R ( 1 / 2 + In 4 / 3 )
♥ So, It's Done ♥ !!
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