please answer it Q. no. 1 and 2
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Volume of 100 g the solution = 100/31.020= 3.22 l
molarity = 15/98 x 3.22
=.0475 mol/l
molality = .153 / .085 = 1.8 mol /kg
molarity = 15/98 x 3.22
=.0475 mol/l
molality = .153 / .085 = 1.8 mol /kg
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