Question

please answer it quick it's very much important ​

Answer 1

Answer:

  [9 × ($\sqrt[3]{64}$ + $\sqrt[3]{125} )^{3}$]^$\frac{1}{4}$

= [9 × $( 9 )^{3}$]^$\frac{1}{4}$ = $9^{4(\frac{1}{4} )}$

= 9

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