Question

Please answer it quick.....



◆The function f:N->R is defined by f(n)=2^n .Then what is the range of the function ?

◆the distance of the point (-2 , 3) from the x-axis is

A)3 B) -3 C)2 D)-2

Please answer both the questions

Best answer would be marked as brainliest...

Answer 1

we have
[tex](a). \\ f(n) = {2}^{n} \\

as n varies from infinity to minus infinity and as exponential power is always positive.
Hence , when n will be infinity the value of function will be infinity and when n will be minus infinity ,function will be (1/infinity ) that will turn to zero.
hence.,
range is (infinity to zero)

(××both infinity and zero are excluded, as both values are not reachable)



(b). I have solved second part graphically ...you can see it from diagram...
OPTION (A) IS CORRECT.
or

you can also use the fact that distance of a point from x axis is y coordinate... and the distance of point from y axis is x coordinate of the point...

for eg.,
if we have a point (a, b)
then distance of point from x axis =b units
and, distance of point from y axis =a units.

thank you...
Mark as brainliest if helped....