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Abc, aed, bcd, dcb, ebd, dbe
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Answer:
Given,
EBC=36°
A/q
We know that all angles of Pentagon=540°
so,all five angles are equal to 108°
hence,let take the angle 1=108°
By carefully observed ∆ABE is isoceles triangle.
Therefor, angle AB=angle AE
Sum all three angle of triangle is =180°
AB+AE+108°=180°
2AB+108°=180°
2AB=180°-108°
2AB=72°
AB=72°/2
AB=36°
Therefore,angleAB=angleAE=36°
All five angles are equal to 108°
hence, angle b also become a 108° when we add 36°.
So,angle 3=36°
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