Question

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Answer 1

Answer:

Solution:

Given-x=2+root3

I  will  solve  only one sum because I  am  very  busy.

Step-by-step explanation:

x+1/x=?

Substitute  the  value  of  x  in  the given  equation.

(2 + root 3 ) + 1/ (2 + root 3)

Take  the  L.C.M

2 + root 3 is the L.C.M

(2+ root 3)(2+ root 3)+(1)/Whole  2 root  3

We  must  rationalize  the factors of denominator.

Multiply the  numerator  and  denominator  by  - 2 root  3

(2 + root 3  )(2+ root  3) +( 1 )/ Whole  2 + root  3  *  -2  root  3/ -2 root  3

Multiply  it .

(4+4 root  3 +3)+1/ whole  2 + root  3 * -2 root  3/-2  root  3

(8+4 root 3/ 2 + root 3) ( 2 - root  3 / 2 - root  3)

16-8 root 3 + 8  root  3 -12/4-3

In  the  denominator  the terms are in a^2-b^2 form .

So:

16-12/1=16-12=4

The   answer  of  the  first  question  is  4 .

In  this way only  u do  remaining  sums .

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