Question

please answer it's really important please

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x) solve

please solve with full explanation and steps please
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Answer 1

Answer:

(x+y)(x-y)+(y-z)(y+z)+(z-x)(z+x)

= x2-y2+y2-z2+z2-x2

=0

note x2=x square

y2=y square

z2=quare

Answer 2

Answer:

0

Step-by-step explanation:

1st step-simply it:

=x^2-y^2+y^2-z^2+z^2-x^2

2nd step-cut off the like terms:

=x^2-x^2-y^2+y^2-z^2+z^2

= 0

I did this by using the formula (a-b)(a+b)=a^2-b^2