Physics, asked by anjalikharb90, 8 months ago

please answer it's urgent ​

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Answered by Anonymous
5

Answer:

 \boxed{\mathfrak{(c) \ 10\sqrt{2} \ kg}}

Explanation:

Force vector applied on a mass is given as:

 \rm \overrightarrow{F} = (8 \hat{i} - 6 \hat{j} + 10 \hat{k}) \: N

Accelration of mass (a) = 1 m/s²

First we will find the magnitude of force vector;

 \rm \implies  |\overrightarrow{F} | =  \sqrt{ {8}^{2} +  {6}^{2}   +  {10}^{2} }   \\  \\ \rm \implies  F =  \sqrt{64 + 36 + 100}  \\  \\ \rm \implies  F =  \sqrt{200}  \\  \\ \rm \implies  F = 10 \sqrt{2} \:  N

According to Newton's second law of motion, Force is equal to mass times accelration i.e.

 \bold{F = ma}

m → Mass of the body

By substituting value in thy equation we get:

 \rm \implies 10 \sqrt{2}  = m \times 1 \\  \\  \rm \implies m = 10 \sqrt{2}  \: kg

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