Question

Please answer it's urgent​

Answer 1

Answer:

$\frac{(x - 1)}{2} \frac{2(x + 1)}{3}$

Answer 2

Question:

• $\footnotesize{\dfrac{x-1}{2}-\dfrac{2(x+1)}{3}=\dfrac{3}{4}   }$
• find the value of x

AnSwEr:

• $\bf{\dfrac{x-1}{2}-\dfrac{2(x+1)}{3}=\dfrac{3}{4}   }$

 

• $\tt{\dfrac{x-1}{2}-\dfrac{2x+2}{3}=\dfrac{3}{4} }$ 

• $\sf{\dfrac{3(x-1)-2(2x+2)}{6}=\dfrac{3}{4}   }$ 

• $\tt{\dfrac{3x-3-(4x+4)}{6}=\dfrac{3}{4}      }$ 

• $\sf{\dfrac{3x-3-4x-4}{6}=\dfrac{3}{4}    }$ 

• $\tt{ \dfrac{(-x-7)}{6}=\dfrac{3}{4}  }$ 

• $\sf{-(x+7)=\dfrac{3}{4}×\dfrac{1}{6}   }$ 

• $\tt{-(x+7)=\dfrac{1}{8}   }$ 

• $\sf{x+7= \dfrac{-1}{8}   }$ 

• $\tt{x=\dfrac{-1}{8}-7   }$ 

• $\sf{x=\dfrac{-1-56}{8}   }$ 

• $\bold{x=\dfrac{-57}{8}   }$