Question

please answer it's very urgent
please it's important please answer please
answer with full steps ​

Answer 1

Answer:

(x^2-y^2)+(y^2-z^2)+(z^2-x^2)

Answer 2

Question

$\footnotesize \tt(x + y)(x - y) + (y + z)(y - z) + (z + x)(z - x)$

$\pmb{\bf{Answer}}$

$= \red0$

❖ Solution

It's given that ;

( x + y )( x - y ) + ( y + z )( y - z ) + ( z + x )( z - x )

We know that , ( a + b )( a - b ) = a² - b².

Therefore,

$\star \footnotesize \tt( x + y )( x - y ) + ( y + z )( y - z ) + ( z + x )( z - x ) \\ = \tt {x}^{2} - {y}^{2} + {y}^{2} - {z}^{2} + {z}^{2} - {x}^{2} \\ = \tt \cancel {x}^{2} - \cancel {y}^{2} + \cancel{y}^{2} - \cancel{z}^{2} + \cancel {z}^{2} - \cancel{x}^{2} \\ = \purple{0}$

$\rule{200pts}{2pts}$

Remember that :-

1. In algebra the sign plays a very important role.

Below are some important sign conventions:

${\boxed{\begin{array}{ c|c} ( - )( - )&( + ) \\ ( - )( + )&( - ) \\ ( + )( - )&( - ) \\ ( + )( + )&( + )\end{array}}}$

• Below are provided some algebraic Identities :-

$\boxed{ \begin{array}{c} \bf( a + b )² = a² + b² + 2ab. \\ \hline\bf( a - b )² = a² + b² - 2ab. \\ \hline\bf( a + b )( a - b ) = a² - b² \\ \end{array}}$

Thankyou