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Let the center be O .
=> We know , that , angle subtended by an arc at the center is TWICE the angle subtended by it on remaining part of the circle .
=> Angle BOC = 2 ( angle BAC )
=> Angle BOC = 2 × 50° = 100°
now , in triangle BOC ,
=> OB = OC = r
therefore , Angle OBC = Angle OCB = x
now ,
=> x + x + 100° = 180° { Angle sum property }
=> 2x = 80°
=> x = 40°
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Step-by-step explanation:
let the centre be o
as angle BAC is 50° so angle BOC is 100°
Now in triangle OBC angle BOC is 100°
then 2x equal to 80°
then xequal to 40°
hope this helps u
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