Question

please answer it step by step​

Answer 1

Answer:

${5}^{2x} = {5}^{ y - 1} \\ 2x = y - 1 \\ 2x + 1 = y \\ \\ {32}^{y} = 4 \times {8}^{x} \\ {2}^{5y} = {2}^{2 + 3x } \\ 10x + 5 = 2 + 3x \\ 7x = - 3 \\ x = \frac{ - 3}{7}$

therefore x=-3/7

and y= 2x+1

=-6/7 +1

=1/7

therefore x is -3/7 and y is 1/7

Answer 2

Answer:

Step-by-step explanation:

25^x=(5)^y-1

((5)^2)^x=5^(y-1)

2x=y-1

2x-y=-1------------------------(1)

32^y=4*8^x

(2^5)^y=2^2*(2^3)^x

2^5y=2^(2+3x)

5y=2+3x

3x-5y=-2-------------(2)

(1) * 5

10x-5y=-5

subtract this from (2)

-7x=3,x=-3/7

from(1)

2*-3/7-y=-1

-6/7-y=-1

y=1-6/7=7/7-6/7=1/7