Question

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Answer 1

The dimension of a and b are [M^ -1 T^ 1 ] and [ ML^2 T^-2 ].

Give the relation as

E = b - x^2 / at

Here

E = energy

X = distance

t = time

we know that ,

The dimension formula

e = [ ML^2 T^-2]

x = [L]

t = [ T]

using principle of homogenecty

e = b .......(1)

[ML^2 T^ -2] = b

e = x^2 / at

at = x^2 / e

at =[ L^2 ]/ [ML^2 T^-2]

at = [M^-1 T^2 ]

a = [M^-1 T ^2] / T

Hence the dimension of the a and b are [ M^-1T ^1 ] and [ML^2T^-2]

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