Question

please answer it was to be correct

if it is you will be report

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Answer 1

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1) d) (6,8,10)

2)

$\sqrt{y} = 6 \\ = y = {6}^{2} \\ = y = 36$

b) 36

Answer 2

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$\Large{\rm{Question \ 1 :}}$

Pythagorean triplets are those 3 numbers which are consecutive and obeys the Pythagoras theorem.

A.T.Q , The Pythagorean triplets are (6,8,10)

$\sf{\rightarrow 6² + 8² = 10²} \\ \sf{\rightarrow 36 + 64 = 100} \\ \sf{\rightarrow 100 = 100}$

$\therefore$ Option D is the correct answer.

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$\Large{\rm{Question \ 2 :}}$

If $\sf{ \sqrt{y} = 6}$, then we have to find the value of y.

Squaring Both Sides

$\sf{\rightarrow \sqrt{y} = 6} \\ \sf{\rightarrow (\sqrt{y})^{2} = 6^2} \\ \sf{y = 36}$

$\therefore$ Option B is the correct answer.

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$\Large{\rm{Question \ 3 :}}$

$\sf{\rightarrow (256)^ {\dfrac{1}{4}}}$

$\sf{\rightarrow [ (2)^{8}]^{ \dfrac{1}{4}}}$

$\sf{\rightarrow (2)^{8 \times \frac{1}{4}}}$

$\sf{\rightarrow (2)^{2}} \\ \sf{\rightarrow 4}$

Now, Inverse that

$\sf{\rightarrow 4^{-1}}$

$\sf{\rightarrow \dfrac{1}{4}}$

$\therefore$ Option C is the correct answer.

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$\Large{\rm{Question \ 4 :}}$

If the x and y are in direct variation, then $\sf{ \dfrac{x}{y} = constant}$

$\sf{\rightarrow \dfrac{4}{16} = constant} \\ \sf{\rightarrow \dfrac{1}{4} = constant}$

$\therefore$ Option C is the correct answer.

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$\Large{\rm{Question \ 5 :}}$

Firstly we will multiply the terms then we will add them.

A.T.Q

$\sf{\rightarrow 3.2 \times 3.2 + 2 \times 3.2 \times 0.8 + 0.8 \times 0.8} \\ \sf{\rightarrow 10.24 + 5.12 + 0.64} \\ \sf{\rightarrow 16}$

$\therefore$ Option B is the correct answer.