please answer it with explanation
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3^2x+1/9=27
3^2x+1=9×27
3^2x+1=3²×3³
by a^m=a^n=. m=n
2x+1=2+3
2x=5-1
x=4/2
x=2
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Solution:
3^2x+1/9 = 27
3^2x+1/3^2 = 3^3
When an exponential equation has the same base on each side, the exponents must be equal.
(2x + 1) - 2 = 3 —- all exponents
2x + (1 - 2) = 3
2x = 3 + 1
2x = 4
x = 2
Hope this will help.
3^2x+1/9 = 27
3^2x+1/3^2 = 3^3
When an exponential equation has the same base on each side, the exponents must be equal.
(2x + 1) - 2 = 3 —- all exponents
2x + (1 - 2) = 3
2x = 3 + 1
2x = 4
x = 2
Hope this will help.
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