Question

Please answer it with explanation.I will mark you as brainlist

Answer 1

Answer:

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$( {\frac{2}{3} })^{5} \times ({ \frac{3}{2} })^{7} = ({ \frac{2}{3} })^{4x} \\ = > ( {\frac{2}{3} })^{5} \times ({ \frac{2}{3} })^{ - 7} = ({ \frac{2}{3} })^{4x} \\ = > ( {\frac{2}{3} })^{5 + ( - 7)} = ({ \frac{2}{3} })^{4x}$

On equating the bases, we get,

$5 + ( - 7) = 4x \\ = > 4x = 5 - 7 \\ = > 4x = - 2 \\ = > x = \frac{ - 2}{4} \\ = > x = \frac{ - 1}{2}$

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