Question

Please answer it with full explanation.

Body A of mass 4m moving with speed u collides with another body B of mass 2m at rest the collision is head on and elastic in nature. After the collision the fraction of energy lost by colliding body A is?

Answer 1

Answer:

Given :-

• Body A of mass 4m moving with speed u collides with another body B of mass 2m at rest the collision is head on and elastic in nature.

To find :-

• After the collision the fraction of energy lost by colliding body A is?

Solution :-

$m_1 = 4m \\ m_2 = 2m$

Fractional loss of KE of colliding body,

$\frac{∆KE}{KE} = \frac{4 \times m_1 m_2}{ {(m_1 + m_2)}^{2} } \\ = \frac{4 \times 4m \times 2m}{ {(4m + 2m)}^{2} } \\ = \frac{32 {m}^{2} }{36 {m}^{2} } \\ = \frac{8}{9}$

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Answer 2

Answer:

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Explanation:

8

-

9

Correct option is

B

9

8

​  

 

Fractional loss of KE of colliding body,

KE

ΔKE

​  

=  

(m  

1

​  

+m  

2

​  

)  

2

 

4×(m  

1

​  

m  

2

​  

)

​  

 

=  

(4m+2m)  

2

 

4×(4m)×2m

​  

 

=  

36m  

2

 

32m  

2

 

​  

=  

9

8

​