Question

please answer it with full method

Answer 1

hope it helps you .....

Answer 2

Here's your answer

BD is a straight line and ray AC stands on it.

Therefore,
angle ACD + angle ACB = 180° (linear pair property)
=> Angle ACB = 180 - angle ACD
=> angle ACB = 180 - 120
=> angle ACB = 60°
=> angle C = 60° ..... (I)

Now, in ∆ABC,

angle A + angle B + angle C = 180° (angle sum property of a ∆)
=> angle B = 180 - (angle A + angle C)
=> angle B = 180 - (60 + 50)
=> angle B = 180 - 110
=> angle B = 70°

$\boxed{\purple{Hence, \: angle \:B\: = \: 70°}}$

Hope it'll help . ;-)