Question

Please answer it
➡️ Wrong Answer will be reported​

Answer 1

S O L U T I O N :

We create data according to the given question;

$\begin{tabular}{|c|c|c|} \cline{1-3} \multicolumn{3} {|c|} {\bf DATA} \\ \cline{1-3} \multicolumn{1} {|c|} { \bf Variety } & \multicolumn {1} {|c|} {\bf Frequency} &\multicolumn{1} {|c|} {\bf f_x} \\ \cline{1-3} \sf 5 &\sf 6 & \sf 30 \\ \cline{1-3} \sf 10 & \sf k & \sf 10k \\ \cline{1-3} \sf 15 & \sf 6 & \sf 90 \\ \cline{1-3} \sf 20 & \sf 10 & \sf 200 \\ \cline{1-3} \sf 25 & \sf 5& \sf 125 \\ \cline{1-3} \bf{TOTAL } & \bf n = (27+k) & \bf f_x = \bf 445 + 10k\\ \cline{1-3} \end{tabular}}$

We get from data :

• Total frequency, (n) = 27 + k
• Total Fx = 445 + 10k

$\underline{\bf{Explanation\::}}$

As we know that formula of the mean;

$\boxed{\bf{Mean\:, (\bar x) = \frac{\Sigma F_x}{n}}}$

$\underline{\underline{\tt{According\:to\:the\:question\::}}}$

$\mapsto\tt{Mean,\:(\bar x) = \dfrac{\Sigma F_x}{n} }$

$\mapsto\tt{15 = \dfrac{445+10k}{27+k} }$

$\mapsto\tt{15(27+k) = 445 + 10k\:\: \underbrace{\sf{Cross-multiplication}}}$

$\mapsto\tt{405 + 15k = 445 + 10k}$

$\mapsto\tt{15k -10k = 445 -405}$

$\mapsto\tt{5k = 40}$

$\mapsto\tt{k = \cancel{40/5}}$

$\mapsto\bf{k = 8}$

Thus,

The value of k will be 8 .

Answer 2

Answer:

S O L U T I O N :

We create data according to the given question;

Step-by-step explanation:

We get from data :

Total frequency, (n) = 27 + k

Total Fx = 445 + 10k

\underline{\bf{Explanation\::}}

Explanation:

As we know that formula of the mean;

\boxed{\bf{Mean\:, (\bar x) = \frac{\Sigma F_x}{n}}}

Mean,(

x

ˉ

)=

n

ΣF

x

\underline{\underline{\tt{According\:to\:the\:question\::}}}

Accordingtothequestion:

\mapsto\tt{Mean,\:(\bar x) = \dfrac{\Sigma F_x}{n} }↦Mean,(

x

ˉ

)=

n

ΣF

x

\mapsto\tt{15 = \dfrac{445+10k}{27+k} }↦15=

27+k

445+10k

\mapsto\tt{15(27+k) = 445 + 10k\:\: \underbrace{\sf{Cross-multiplication}}}↦15(27+k)=445+10k

Cross−multiplication

\mapsto\tt{405 + 15k = 445 + 10k}↦405+15k=445+10k

\mapsto\tt{15k -10k = 445 -405}↦15k−10k=445−405

\mapsto\tt{5k = 40}↦5k=40

\mapsto\tt{k = \cancel{40/5}}↦k=

40/5

K=8