Question

please answer its very urgent...​

Answer 1

Answer:

Step-by-step explanation:

$\frac{2x}{x-3}$ + $\frac{1}{2x+3}$ + $\frac{3x+9}{(x-3)(2x-3)}$ = 0 ( x ≠ 3, - $\frac{3}{2}$ )

$\frac{2x(2x+3)(2x-3)+(x-3)(2x-3) + (3x+9)(2x+3)}{(x-3)(2x-3)(2x+3)}$ = 0

2x(4x² - 9) + 2x²- 9x + 9 + 6x² + 27x + 27 = 0

8x³ - 18x + 2x² - 9x + 9 + 6x² + 27x + 27 = 0

8x³ + 8x² + 36 = 0

2x³ + 2x² + 9 = 0

x ≈ - 2.06