Math, asked by ak3130892, 3 months ago

please answer jaldi​

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Answered by somyakumarijha7579
0

Step-by-step explanation:

1(a) perimeter of rectangle = 2(l+b)

=2(12+8)cm

=24+16cm

=40cm

(b)a) perimeter of square=4a

=4*6cm

=24cm

b) perimeter of square=4a

=4*11m

=44m

c) perimeter of square=4a

=4*26cm

=104cm

(c) perimeter of triangle=sum of all sides

=6+8+10cm

=24cm

(d) perimeter=2(l+b)

=2(35+20)

=2*55m

=110m

(e) perimeter=2(l+b)

=2(36+15)

=2*51cm

=102cm

(f) perimeter=4a

=4*12cm

=48cm

(g) perimeter=2(l+b)

=2(62+40)

=2*102m

=204m

(h) perimeter of rectangle (Tina)=2(l+b)

=2(12+8)

=2*20m

=40m

perimeter of square (Meena)=4a

=4*11m

=44m

Meena covered more distance by(44-40)

So,Meena covered more distance by 4m

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Answered by himanisharma2292004
2

Answer:

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