Please answer little urgent
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The resistance of the group of 3 resistors is equal to
R = 30 V / 7.5 A =
4 ohm.
Let R3 be the resistance of the third resistor, then
1/R =
1/10 + 1/12 + 1/R3
so,
1/4 = 1/10 + 1/12 + 1/R3
1/R3 = 1/4
- 1/10 - 1/12
= 15/60 - 6/60 - 5/60
= 4/60
hence
R3 = 60/4 = 15 ohm
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