Question

Please answer!!!!! Look over Chuck's work What is incorrect about the way Chuck interpreted his problem? What should have been a clue to Chuck that something was wrong?

Answer 1

Step-by-step explanation:

your answer is here mate

Answer 2

✪ᴀɴsᴡᴇʀ✪

• Required Probability = 0.0136.

★ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ★

Let

• A = Student takes chemistry
• B = Student takes algebra 2.

☆ɢɪᴠᴇɴ☆

• Probability that a student takes algebra 2 is 8%. So, P(B) = 0.08

• Probability that a student who is taking algebra 2 will also be taking chemistry is 17%.So, P(A|B) = 0.17

☆ᴛᴏ ғɪɴᴅ☆

• Probability that a random student will be taking both algebra 2 and chemistry i. e. P(A∩B)

☆ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴ☆

We know that

$P(A|B) = \frac{P(A∩B)}{P(B)}$

$⇒P(A∩B) = P(A|B)P(B)$

$⇒P(A∩B) = 0.17 \times 0.08$

$⇒P(A∩B) = 0.0136$

᯽CLUE THAT INTERPRETATION IS WRONG᯽

A∩B is a subset of B. As such there is less or equal number of elements in A∩B in comparison with B. So P(A∩B) will be always less than or equal to P(B).

In the work shown, P(A∩B) > P(B). As soon as you see it, it can be concluded that something is wrong.