please answer....math question
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chord AB is of 10 cm.
radius is 5 cm....so diameter will be 10 that is (2×5).
now we know that the diameter of a circle is the longest chord of a circle ...so we can say that chord AB is the diameter of circle....
now arc is the semicircle( half the perimeter) without adding the extra radius....so it will be...
=(2Πr)÷2
=Πr
=(22×10)÷7
=31.4cm approx
hope it may help u
radius is 5 cm....so diameter will be 10 that is (2×5).
now we know that the diameter of a circle is the longest chord of a circle ...so we can say that chord AB is the diameter of circle....
now arc is the semicircle( half the perimeter) without adding the extra radius....so it will be...
=(2Πr)÷2
=Πr
=(22×10)÷7
=31.4cm approx
hope it may help u
vaishu564:
ok
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