Math, asked by kvnmurthy19, 1 year ago

Please answer maths legends and genius

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Answered by siddhartharao77
5

Answer:

9 bottles

Step-by-step explanation:

Diameter of hemispherical bowl = 9 cm.

Inner radius of hemispherical bowl = 4.5 cm.

Volume of the hemispherical bowl

= (2/3) πr³

= (2/3) * (22/7) * (4.5)³

= 190.92 cm³.


Diameter of cylindrical bottles = 3 cm.

∴ Radius of cylindrical bottles = 3/2 cm.

Height of cylindrical bottle h = 3 cm.

Volume of cylindrical bottle:

= πr²h

= (22/7) * (3/2)² * 3

= 21.214 cm³


Number of bottles required:

⇒ Volume of the hemispherical bowl/volume of the cylindrical bottle

⇒ 190.92/21.214

⇒ 9.


Therefore,number of bottles required = 9.


Hope it helps!

Answered by abhi569
6

Answer:

9 bottles are required.


Step-by-step explanation:

We know that the volume of hemispherical bowl = 2 / 3 πr^2 , where r is the radius of the bowl.

So,

Volume of the bowl = 2 / 3 π ( diameter )^2

       ⇒ 2 / 3 x 22 / 7 x ( 9 / 2 )^3 cm^2

       ⇒ 2 / 3 x 22 / 7 x 243 / 8 cm^2

       ⇒ 11 x 27 x 9 / 14

       ⇒ 2673 / 14


Now, if we fill the water in the bottles ( of the given measurements ).

Volume of bottle = Total amount of water in 1 bottle


As, we know that the volume of bottle( cylinder ) is πr^2 h.

Total amount of water in bottle = 22 / 7 x ( 3 / 2 )^2 x 3 cm^2

Total amount of water in bottle = 594 / 28 cm^2



Now,

Bottles required = volume of bowl / total amount of water in one bottle

Bottles required = ( 2673 / 14 ) / ( 594 / 28 )

Bottles required = 2673 x 2 / 594

Bottles required = 9



Therefore 9 bottles are required to be filled with liquid.

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