please answer maths legends please
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▶ Question - Find :
(i) the lateral or curved surface area of a closed cylindrical petrol storage tank that is 4.2 m in diameter and 4.5 m high.
(ii) how much steel was actually used, if 1/12 of the steel actually used was wasted in making the tank.
▶ Explanation :-
Height ( h ) of cylindrical tank = 4.5 m
Radius ( r ) of the circular end of cylindrical tank = ( 4.2 / 2 ) = 2.1 m
i) Lateral or curved surface area of tank = 2πrh
= 2 × 22 / 7 × 2.1 × 4.5
= 44 × 0.3 × 4.5
= 59.5 m^2
Therefore, CSA of tank = 59.5 m^2
ii) Total surface area of tank = 2πr ( r + h )
= 2 × 22 / 7 × 2.1 ( 2.1 + 4.5 )
= 44 × 0.3 × 6.6
= 87.12 m^2
Let A m^2 steel sheet be actually used in making the tank
=> A ( 1 - 1 / 12 ) = 87.12
=> A ( 11 / 12 ) = 87.12
=> A = 87.12 × 12 / 11
=> A = 95.04 m^2
Therefore, 95.04 m^2 steel was used in actual while making such a tank
Similar questions
(i) Given, diameter = 4.2m
Radius = 2.1m
Height = 4.5m
Total surface area = 2πr(r + h)
= 2 × 3.14 × 2.1 × (2.1 + 4.5)
= 87m2
(ii) if  of the steel was wasted in making the tank. The sheet used in making the tank = (1−) × 87
=  × 87
= 79.75m2