Question

Please Answer Me....​

Answer 1

Answer:Ionisation potential is the potential calculate from the orbit n=1 to the n = infinity and that is given as:

E = > 13.6 × z²

z²= 20/13.6............(1)

Excitaion energy is given as :

=> -13.6 × (z² / 4 – z² / 1)

from equation . (1) we get,

=> -13.6 × (5/13.6 – 20/13.6)

=> 15 V

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