Question

please answer me .........​

Answer 1

Let the 3 terms be a+1,a,a-1

Therefore, a+d+a+a-d=21. 3a =21 a=7. a+d×a-d =a+6. a^2-d^2=a+6. 49-d^2=13 = -d^2=13-49=d^2=36 therefore,d=6.therefore the 3 terms are 13,7,6.Hope it helps.

Answer 2

Answer:

1 ,7, 13 or 13 , 7 , 1

Step-by-step explanation:

Let consider a-d . a , a+d as three term

sum of three terms are

a-d+a+a+d=21

3a=21

a=7

product of first and third exeeds second term by 6

(a-d)(a+d)=a+6

$a ^{2} + ad - ad - d ^{2} = a + 6$

a2-d2=a+6. put a=7

d=+6 or -6

by using +6 the three terms are 1, 7, 13

by using -6 the three terms are 13, 7 , 1