Math, asked by Ansikapal, 9 months ago

please answer me!!!​

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Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
18

\huge\sf\blue{Given}

\sf AD = CF

\sf AB = DE

\sf\angle BAC = \angle EDF

\rule{110}1

\huge\sf\gray{To\;Prove}

◈ ∆ABC = ∆DEF

\rule{110}1

\huge\sf\purple{Steps}

In ∆ABC & ∆DEF

\sf AD = CF

\sf AB = DE

\sf\angle BAC = \angle EDF

\sf\therefore \triangle ABC \cong \triangle DEF \: \bigg\lgroup SAS \bigg\rgroup

\sf Hence \ Proved !!

\rule{170}3

Answered by Anonymous
7

Step-by-step explanation:

♻️ANSWER♻️

✏️AB=CF

✏️AB=DE

✏️∠BAC=∠EDF

∆ABC≅∆DEF

(By the rule of SAS)

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