Question

Please answer me . ​

Answer 1

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\dashrightarrow \angle AOB= x+2$

$\dashrightarrow \angle BOC =2x+16$

$\dashrightarrow \angle COD= 3x$

$\large\underline\bold{TO\:FIND,}$

$\dashrightarrow Value\:of\: \angle BOC$

$\large\underline\bold{SOLUTION,}$

$\dashrightarrow first\:finding\:the\:value\:of\:x$

$\therefore by\:angle\:some\:property,$

$\dashrightarrow \angle AOB+ \angle BOC+ \angle COD = 180\degree$

$\implies (x+2)+(2x+16)+3x=180\degree$

$\implies x+2x+3x+2+16=180\degree$

$\implies 6x+18=180\degree$

$\implies 6x=180-18$

$\implies 6x= 162$

$\implies x= \dfrac{162}{6}$

$\implies x= \cancel\dfrac{162}{6}$

$\implies x= 27$

$\large{\boxed{\bf{ \star\:\:x=27\degree \:\: \star}}}$

NOW,SUBSTITUTING VALUE OF x ,

we get,

$\implies \angle BOC= 2x+16\\ \implies 2(27)+16\\ \implies 54+16\\ \implies 70\degree$

$\large{\boxed{\bf{ \star\:\: \angle BOC= 70\degree\:\: \star}}}$

$\large\underline\bold{VALUE\:OF\: \angle BOC\:IS\:70\degree}$

_____________

Answer 2

given:-

$\dashrightarrow \angle AOB= x+2$

$\dashrightarrow \angle BOC =2x+16$

$\dashrightarrow \angle COD= 3x$

To find:-

$\dashrightarrow Value\:of\: \angle BOC$

Answer:-

VALUE OF < BOC IS 70°

explanation in details:-

$\dashrightarrow first\:finding\:the\:value\:of\:x$

$\dashrightarrow \angle AOB+ \angle BOC+ \angle COD = 180\degree$

$\implies (x+2)+(2x+16)+3x=180\degree$

$\implies x+2x+3x+2+16=180\degree$

$\implies 6x+18=180\degree$

$\implies 6x=180-18$

$\implies 6x= 162$

$\implies x= \dfrac{162}{6}$

$\implies x= \cancel\dfrac{162}{6}$

$\implies x= 27$

$\large{\boxed{\bf{ x=27\degree}}}$

NOW,SUBSTITUTING VALUE OF x ,

we get,

$\implies \angle BOC= 2x+16\\ \implies 2(27)+16\\ \implies 54+16\\ \implies 70\degree$

$\large{\boxed{\bf{ \angle BOC= 70\degree}}}$

$\rm\underline\bold{\pink{VALUE\:OF\: \angle BOC\:IS\:70\degree}}$