Question

please answer me ........​

Answer 1

Answer:

90 degree

I think so

If correct mark me as branliest

Answer 2

Answer:

In the triangle BCD

cosα=p2+q2q and sinα=p2+q2p

Using sine rule in triangle ABD

sinθAB=sin(θ+α)BD

⇒AB=sinθcosα+cosθsinαp2+q2sinθ=p2+q2sinθ⋅q+p2+q2cosθ⋅pp2+q2sinθ

⇒AB=(pcosθ+qsinθ)(