Math, asked by manavbosco11, 1 year ago

please answer me 5th 6th and 7th

Attachments:

Anonymous: 5- No, 6- 1 & 7 - 16.

KickB: Q.5 no 8^n cannot end with 0 because its prime factorisation does not have both 2^n and 5^m for some no. n and m

Anonymous: perfect :)

Answers

Answered by arnav9999

5th

it can be done by using cyclicity and the cyclicity of 8 is 4 that comprises of 8,4,2 and 6

so it will never end with 0

6th

co prime then hcf will be 1

7th

hcf of 48 and 80 is 16

arnav9999: if you found it good please mark it as brainliest one

Answered by Blue14

Answer:

(5)

For a number to end with the digit 0 it's prime factorization should have 2 and 5 as a common factor.

here 8^n = (2*4)^n doesn't have 5 in its prime factorization.

Therefore 8^n cannot end with the digit 0.

(6)

tep-by-step explanation:

Given : p and q are two co-prime numbers

To find : Their HCF and LCM

Solution :

Since, p and q are two co-prime numbers

Co-primes means only common factor is 1.

HCF is the highest common factor.

So, HCF(p,q)=1

To find LCM, we know that

Product of two numbers = HCF × LCM

p × q = 1 × LCM

(7)

HCF of 48 & 80= d

48= 2×2×2×2×3

80= 2×2×2×2×5

So, HCF of 48 & 80= 2⁴=16

Hence, d=16

HOPE IT WILL HELP YOU❤☺

Blue14: Plz mark as brainliest

manavbosco11: thanks mate

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