please answer me 5th question
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Hi ,
f( x ) = 2x³ - 3x²+ax + b
i ) if x = 0 is the root of f ( x ) then
f( 0 ) = 0
2 ( 0 )³ - 3 ( 0 ) ² + a × 0 + b = 0
b = 0 ----( 1 )
ii ) if x = - 1 then
f ( - 1 ) = 0
2 ( - 1 )³ - 3 ( - 1 )² + a ( -1 ) + b = 0
-2 -3 - a + 0 = 0 since b= 0
-5 - a = 0
-a = 5
a = -5
Therefore ,
a = -5 , b = 0
I hope this helps you.
f( x ) = 2x³ - 3x²+ax + b
i ) if x = 0 is the root of f ( x ) then
f( 0 ) = 0
2 ( 0 )³ - 3 ( 0 ) ² + a × 0 + b = 0
b = 0 ----( 1 )
ii ) if x = - 1 then
f ( - 1 ) = 0
2 ( - 1 )³ - 3 ( - 1 )² + a ( -1 ) + b = 0
-2 -3 - a + 0 = 0 since b= 0
-5 - a = 0
-a = 5
a = -5
Therefore ,
a = -5 , b = 0
I hope this helps you.
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