Question

please answer me 6a​

Answer 1

Step-by-step explanation:

91/2,71/5,23/4,31/9

=19/2. 36/5. 11/4. 28/9

=11/4<28/9<36/5<19/2

=

=in ascending order

=23/4,31/9,71/5,91/2

adding smallest and greatest fraction we get

11/4+19/2

11+38/4

=49/4

Answer 2

Given,

$\huge \frak{9 \frac{1}{2}, \: \: 7 \frac{1}{5} , \: \: 2 \frac{3}{4} , \: \: 3 \frac{1}{9} }\\ \\ \boxed{ \frak{= > \frac{19}{2} , \: \frac{36}{5} , \: \frac{11}{4} , \: \frac{28}{9} }}$

Making the fractions' denominators like, we get,

$\boxed{ \frac{19 \times 90}{2 \times 90} = \frac{1710}{180} }\\ \boxed{\frac{36 \times 36}{5 \times 36} = \frac{1296}{180} } \\ \boxed{ \frac{11 \times 45}{4 \times 45 } = \frac{495}{180} } \\ \boxed{ \frac{28 \times 20}{9 \times 20} = \frac{ 560}{180} }$

Now,

• Sum of greatest and smallest fractions =

$\huge \frac{1710}{180} + \frac{495}{180} \\ \\ \\ = > \frac{1710 + 495}{180} \: = \red{\frac{2205}{180}}$

• Arrangement of fractions in ascending order,

$\frac{495}{180} < \frac{560}{180} < \frac{1296}{180} < \frac{1710}{180} \\ \\ = > \red {\frac{11}{4} < \frac{28}{9} < \frac{36}{5} < \frac{19}{2} }$