Question

please answer me.... .......

Answer 1

$AB {}^{2} + BC {}^{2} = (6 \sqrt{3} ) {}^{2} + (6) {}^{2} \\ = > 108 + 36 \\ = > 144 = > (12) {}^{2} = AC {}^{2}$

By inverse of Pythagoreous theorem.we conclude that.

∆ABC is a right triangle at B.

=> ∠B= 90°