Question

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Anderson my question ​

Answer 1

sum of the roots is -b/a _____(3)

sum of cubes of their reciprocals is (1/a^3 )+ (1/b^3)

i.e (a^3+b^3)/(ab)^3 _____ (1)

a^3+b^3 = (a+b)^3 - 3(ab)(a+b) _______(2)

here a+b is sum of roots i.e -b/a

(ab) is product of roots i.e c/a

by (1);(2) u get some relation in a,b the equal it to (3)

you get the answer

I think this may help you