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Answered by chetna365
1

Answer:

11th term of AP is -30.

Explanation:

The first term [a] = -5

number of terms [n] = 11

common difference [d] = -5 - [-5/2]

                                      = -5 + 5/2

                                      = -10/2+5/2

                                      = -5/2

formula = a subscript n= a+(n-1)d

       a subscript 11 = -5 + (11-1)-5/2

                              = -5+ (10) -5/2

                              = -5 + 5 (-5)

                              = -5 -25

                              = -30

                   

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