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Answer:
11th term of AP is -30.
Explanation:
The first term [a] = -5
number of terms [n] = 11
common difference [d] = -5 - [-5/2]
= -5 + 5/2
= -10/2+5/2
= -5/2
formula = a subscript n= a+(n-1)d
a subscript 11 = -5 + (11-1)-5/2
= -5+ (10) -5/2
= -5 + 5 (-5)
= -5 -25
= -30
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