please answer me anyone fast
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Answer:
QRS=107 RQS=43 PRQ=52
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Answer:
solution-
to find-
Given:PQRS is a cyclic quadrilateral
∆QPS =73° ∆PQS =55° and ∆PSR =82°
1} opposite angle of a cyclic quadrilateral is supplementary
= ∆QPS + ∆QRS = 180°
=73°+∆QRS = 180°
= ∆QRS= 180° - 73 = 107°
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