Question

Please answer me as fast as possible

Answer 1

Hope it helps

Use identity (a+b)^2

And (a-b)^2

Answer 2

$(2x + 4) ^{2} - {(x - 5)}^{2} = 26x \\ = > {(2x)}^{2} + 2 \times 2x \times 4 + {4}^{2} - ({x}^{2} - 2 \times x \times 5 + {5}^{2} ) = 26x \\ = > {4x}^{2} + 16x + 16 - {x}^{2} + 10x - 25 = 26x \\ = > {3x }^{2} + 26x - 9 = 26x \\ = > {3x}^{2} = 26x - 26x + 9 \\ = > {3x }^{2} = 9 \\ = > {x}^{2} = \frac{9}{3} \\ = > {x}^{2} = 3 \\ = > x = \sqrt{3}$
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