Math, asked by nandni12, 1 year ago

please answer me as fast as u can

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siddhartharao77: Option (B)

Answers

Answered by ironomkar
1
option C is the right maybe


hope it help



report nonsense answers
Answered by siddhartharao77
0
Given Equation is (5x^2 + 14x + 2)^2 - (4x^2 - 5x + 7)^2

We know that (a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca.

We know that (a - b + c)^2 = a^2 + b^2 + c^2 - 2ab - 2bc + 2ca

= [25x^4 + 196x^2 + 4 + 2(5x^2 * 14x) + 2(14x * 2) + 2(2 * 5x^2)] - [16x^4 + 25x^2 + 49 - 2(4x^2 * 5x) - 2(5x * 7) + 2(7 * 4x^2)

= 25x^4 + 196x^2 + 4 + 140x^3 + 56x + 20x^2 - 16x^4 - 25x^2 - 49 + 40x^3 + 70x - 56x^2


= 9x^4 + 180x^3 + 135x^2 + 126x - 45.



Now,


We have to divide this by (x^2 + x + 1).



                   9x^2 + 171x - 45
                  --------------------------------------------------
x^2 + x + 1) 9x^4 + 180x^3 + 135x^2 + 126x - 45

                   9x^4 +  9x^3  +   9x^2

                   ------------------------------------------------------

                               171x^3  +  126x^2  +  126x

                               171x^3  +  171x^2   +   171x 

                   -----------------------------------------------------------

                                                - 45x^2  -  45x   - 45

                                                - 45x^2  -  45x   -  45

                      ----------------------------------------------------------

                                                               0.




Therefore the quotient is 9x^2 + 171x - 45 (or) 9(x^2 + 19x - 5) with a remainder 0.




Hope this helps! --------------------- Good Luck!

siddhartharao77: Brainliest it as fast as u can.
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