Question

please answer me back to the question​

Answer 1

Question

Water is flowing at the rate of 15 km per hour through a cylindrical pipe of diameter 14 cm into a cuboidal pond which is 50 cm long and 44 cm metre. In what time the level of the water in pond rise by 21 cm?

Answer

1.2 minutes or 72 seconds

Explanation

Given water is flowing at the rate of 15 kmph

→ Length of water flowing in pipe in 1 hour = 15 km = 15000 m

Diameter of cylindrical pipe = 14 cm = 7 cm = 0.07 m

Area of cross section of pipe = πr² = 22/7 × 0.07 × 0.07

→ 0.0154 m²

Total volume of pipe entering the pipe in 1 hour = 15000 × 0.0154 m³

→ 231 m³

Now, the time in which level of water in pond rise by 21 cm is asked

So, we will calculate volume of water required to raise the level

→ Volume of cuboid = l × b × h

l = 50 cm = 0.5m

b = 44 m

h = 21 cm = 0.21 m

→ 0.5 × 44 × 0.21

→ 4.62 m³

In pipe, 231 m³ of water enters in 1 hour = 60 minutes

→ time in which 1 m³ of water enters in the pipe = 60/231 minutes

→ time in which 4.62 m³ of water enters in the pipe = 60/231 × 4.62 minutes

→ 1.2 minutes or 72 seconds.

Answer 2

Hey Pretty Stranger!

$\large \red { \sf \: Here \: you \: go!}$

$\textbf{\underline{\underline{Measurements\:of\:Tanks:}}}$

$\sf \blue{Length = 50 \: m }$

$\sf \blue{ Breadth = 44 \: m }$

$\sf \blue{ Height = 21 cm = 0.21 \: m }$

$\textbf{\underline{\underline{Volume\:of\:water:}}}$

$\boxed{ \purple{ \: \sf \: Volume = length \times breadth \times height}}$

$\implies \sf \: 50 \times 44 \times 0.21$

$\implies \boxed{ \red{ \sf \: 462 {m}^{3} }}$

$\textbf{\underline{\underline{Measurements\:of\:Cylinders:}}}$

$\sf \blue{Radius = 7cm = 0.07 \: m }$

$\sf \blue{Length = 15 \: km = 15000 \: m}$

$\boxed{ \purple{ \sf \: Height = \frac{Volume }{Area \: of \: circle} }}$

$\implies \sf \: \dfrac{462}{ \dfrac{22}{7} \times {0.7}^{2} }$

$\implies \sf \: \dfrac{462}{0.0154}$

$\implies \sf \: \dfrac{462}{0.0154}$

$\implies \boxed{ \red{ \sf \: 30000 \: m }}$

$\textbf{\underline{\underline{Time\:Taken :}}}$

$\sf \: \cancel \dfrac{30000}{15000}$

$\implies \boxed{ \red{ \sf \:2 \: hours \: }}$