Question

please answer me blue tick question ​

Answer 1

Answer:

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Step-by-step explanation:

and c

dx

dy

=

xy+x

xy+y

=

x(1+y)

y(1+x)

y

(1+y)

dy=

x

(1+x)

dx

⇒(

y

1

+1)dy=(

x

1

+1)dx

Now, integrate on both sides we get

logy+y=logx+x+logC

log

x

y

=x−y+logC

x

y

=ce

x−y

y=xce

x−y

ans e

=(p

2

+q

2

−r

2

+2pq)(p

2

+q

2

−r

2

−2pq)

=(p

2

+q

2

+2pq−r

2

)(p

2

+q

2

−2pq−r

2

)

=[(p+q)

2

−r

2

][(p−q)

2

−r

2

]

=(p+q+r)(p+q−r)(p−q+r)(p−q−r)