Question

Please answer me correctly

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Answer 1

Step-by-step explanation:

In the question, it's been stated to fill in the blanks of a few sub-questions with appropriate answers. Let's pinpoint them one by one!

11.⠀⠀4x + 3 = 5

⠀ ⠀ ⠀so x = ?

We've to solve the equation to find the value of x.

$\twoheadrightarrow{ \sf{4x + 3 = 5}}$

Transposing the like term to the R.H.S.

$\twoheadrightarrow{ \sf{4x = 5 - 3}}$

Simplifying the R.H.S.

$\twoheadrightarrow{ \sf{4x = 2}}$

Again transposing the like term from L.H.S. to R.H.S.

$\twoheadrightarrow{ \sf{x = \dfrac{2}{4} }}$

Again simplifying the R.H.S.

$\twoheadrightarrow \underline{ \boxed{ \frak\red{x = \dfrac{1}{2} \: (or) \: 0.5 }}}$

⠀⠀⠀⠀⠀━━━━━━━─━━━━━━━

12.⠀⠀3x – 1 = 2

⠀ ⠀ ⠀so x = ?

In order to find the value of x, we will have to solve the given equation.

$\twoheadrightarrow{ \sf{3x - 1 = 2}}$

Transposing the like term from L.H.S.

$\twoheadrightarrow{ \sf{3x = 2 + 1}}$

Adding the numericals in the L.H.S.

$\twoheadrightarrow{ \sf{3x = 3}}$

Transposing the like term, once again.

$\twoheadrightarrow{ \sf{x = \dfrac{3}{3} }}$

Reducing the fraction to its lowest form in the L.H.S.

$\twoheadrightarrow \underline{ \boxed{ \frak\red{x = \dfrac{1}{1} \: (or) \: 1 }}}$

⠀⠀⠀⠀⠀━━━━━━━─━━━━━━━

13.⠀⠀If x = –13/17

⠀ ⠀ ⠀so – (–x) = ?

We know that x = –13/17. So, (–x) will also be –13/17 since the value in the R.H.S. is already in negative.

As per the question, we have to find the value of – (–x). Writing it in the required form:

$\twoheadrightarrow{ \sf{ - \bigg( - \dfrac{13}{17} \bigg) }}$

We all have learnt about the symbol change while solving and simplifying algebraic equations/expressions. With this knowledge, we can say that, when (–) and (–) integers are operated, they will be turned into positive integer. Hence,

$\twoheadrightarrow \underline{ \boxed{ \frak\red{ - ( - x) = + \: \dfrac{13}{17} \: (or) \: \dfrac{13}{17} }}}$

⠀⠀⠀⠀⠀━━━━━━━─━━━━━━━

14.⠀⠀Multiplicative inverse of –13/19 is ?

Multiplicative inverse of any integer is nothing but the reciprocal of the integer. Hence, the multiplicative inverse of –13/19 can be simply obtained by interchanging the values of its numerator and denominator with each other.

$\twoheadrightarrow \underline{ \boxed{ \frak\red{( \times ) \: inverse = \dfrac{ - 19}{13} }}}$

⠀⠀⠀⠀⠀━━━━━━━─━━━━━━━

15.⠀⠀x – 1 = 14

⠀ ⠀ ⠀so x = ?

Solving the equation:

$\twoheadrightarrow{ \sf{x - 1 = 14}}$

Transposing the like term from the L.H.S. to the R.H.S.

$\twoheadrightarrow{ \sf{x = 14 + 1}}$

Simplifying the R.H.S. part.

$\twoheadrightarrow \underline{ \boxed{ \frak\red{x = 15 }}}$

⠀⠀⠀⠀⠀━━━━━━━─━━━━━━━

16.⠀⠀2x – 3 = 5x

⠀ ⠀ ⠀x = ?

This equation should also be solved to obtain the value of x. Let's do it!

$\twoheadrightarrow{ \sf{2x - 3 = 5x}}$

Transposing the like terms.

$\twoheadrightarrow{ \sf{- 3 = 5x - 2x}}$

Simplifying the R.H.S. part.

$\twoheadrightarrow{ \sf{- 3 = 3x}}$

Again performing transposition.

$\twoheadrightarrow{ \sf{ \dfrac{ - 3}{3} = x}}$

$\twoheadrightarrow{ \sf{x = \dfrac{ - 3}{3}}}$

Simplifying the R.H.S.

$\twoheadrightarrow \underline{ \boxed{ \frak\red{x = \dfrac{ - 1}{1} \: (or) \: - 1 }}}$

All the answers have been obtained. Cheers!