Question

please answer me fast 10 standard​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Let there be a value of x such that the sum of the number of the houses preceding the house numbered x is equal to the sum of the numbers of the houses following it

House H1 ,H2,H3.......Hx−1 ,HHx1 ........H49

House No. 1 2 3 .......... x -1 x + 1..............49

House number will form an A.P whose first term and the common difference is 1

Sum of n terms S= n/2 [2a+(n−1)×d]

Sx−1=S49 −Sx

⇒ (x−1)/2

[2(1)+(x−1−1)1]= 49/2

[2+48]− x/2 [2(1)+(x−1)1]

⇒ x−1/2 [2+(x−2)]= 49/2 [50]− x/2[2+x−1]

⇒ x−1/2 [x]= 49/2

[50]− x/2[x+1]

⇒ x/2 [x−1+x+1]= 49/2 [50]

⇒ x/2[2x]=49×25

⇒x^2=49×25

⇒x=7×5=35.

Since x is not a fraction hence the value of x satisfying the given condition exists and is equal to 35.

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