Question

please answer me fast​.

Answer 1

Step-by-step explanation:

If ABllCD and EF is the transverse.

Then,

AEG=DHF(corresponding angle)

so, AEG=DGF=35*(TAKE * MARK AS DEGREE)

Then in triangle AEG,AGF is the exterior angle.

so,

AEG plus EAG=AGH(exterior angle)

so,

AGH=65* plus 35*

=100*