Question

Please answer me fast

Answer 1

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Answer 2

Answer:

${2x}^{2} + \frac{5x}{3} - 2 = 0 \\ \\ \frac{ {6x }^{2} + 5x - 6 }{3} = 0 \\ {6x}^{2} + 5x - 6= 0 \\ {6x}^{2} + 9x - 4x - 6 = 0 \\ 3x(2x + 3) - 2(2x + 3) = 0 \\( 3x - 2)(2x + 3) = 0 \\ either \: \: \: 3x - 2 = 0 \: \: \: \: \: or \: \: \: \: \: \: \: 2x + 3 = 0 \\ 3x = 2 \: \: \: \: \: \: and\: \: \: \: \: \: 2x = - 3 \\ x = \frac{2}{3} \: \: \: \: \: \: \: and\: \: \: \: \: \: \: x = \frac{ - 3}{2} \\ x = \frac{2}{3} \: \: \: and \: \: \: \: \: \frac{ - 3}{2}$