Question

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Answer 1

Answer:

1. median=mean of n/2 and n/2 +1 th observations

24 =x+2+x+4/2

24 =2x+6/2

24 =x+3

hence,x=21

2.lower limit=130

upper limit=150

hence,class mark =130+150/2

=280/2

=140

3.from properties of quadrilateral,

angleBOD=2×angleBPD

160=2×angleBPD

AngleBPD=80°

4.surface area of sphere=4×22/7×r^2

r^2=154×7/22×1/4

=7×7×1/4

r=(49/4)^1/2

therefore,r=7/2=3.5cm^2

5.from the figure,RS=2OR=2OS______(1)

PQ=2OP=2OQ

area of triangle PQR=1/2×OR×PQ_______(2)

and area of triangle PQS=1/2×OS×PQ

from (1),OR=OS

hence area of PQS=1=2×OR×PQ_______(3)

from (2),(3) area of PQR=area of PQS

Hence proved

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