please answer me fast
Attachments:
Answers
Answered by
0
Answer:
Step-by-step explanation:
In such question, we first take 'x' to positive and then 'x' to be negative and solve for both the cases.
When 'x' is positive-:
x²-x+4 = 2x²-3x+1
x²-2x-3=0
(x-3)(x+1)
x=3,-1
When 'x' is negative-:
x²+x+4 = 2x²+3x+1
x²+2x-3=0
(x+3)(x-1)
x=-3,1
Therefor for x = -3,-1,1,3 are the solution to the equation.
Answered by
0
Answer:
follow me
Step-by-step explanation:
answer is that question by a u
Similar questions