Math, asked by slata9100, 10 months ago

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Answered by punit2508
0

Answer:

Step-by-step explanation:

In such question, we first take 'x' to positive and then 'x' to be negative and solve for both the cases.

When 'x' is positive-:

x²-x+4 = 2x²-3x+1

x²-2x-3=0

(x-3)(x+1)

x=3,-1

When 'x' is negative-:

x²+x+4 = 2x²+3x+1

x²+2x-3=0

(x+3)(x-1)

x=-3,1

Therefor for x = -3,-1,1,3 are the solution to the equation.

Answered by aniketpasi201454
0

Answer:

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Step-by-step explanation:

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