Question

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Answer 1

Answer:

hope this helps you......

Answer 2

Answer :

The required fraction is 5/9

Given :

• The sum of the numerator and denominator of a fraction is 4 more than twice the numerator.
• When the numerator and denominator are increased by 3 , they are in the ratio 2:3

To Determine :

• The fraction

Solution :

Let us consider the numerator be x and denominator be y

Therefore, the fraction is

$\bf \dfrac{x}{y}$

According to Question :

$\sf \implies x + y = 4 + 2x \\\\ \sf \implies y = 4 + 2x - x \\\\ \sf \implies y = 4 + x ...........(1)$

Again from question :

$\sf \implies \dfrac{x+3}{y+3} = \dfrac{2}{3} \\\\ \sf \implies 3(x + 3) = 2(y + 3) ...........(2)$

Now putting the value of y in (2) :

$\sf \implies 3(x + 3) = 2( 4 +x + 3) \\\\ \sf \implies 3x + 9 = 2x + 14 \\\\ \sf \implies 3x - 2x = 14 - 9 \\\\ \bf \implies x = 5$

Using the value of x in (1) :

$\sf \implies y = 4 + 5 \\\\ \bf \implies y = 9$

Thus the required fraction is

$\bf \longrightarrow \dfrac{5}{9}$